<script language="JavaScript>
x = prompt("Please enter a number");
answer = x % 72
alert("The answer is " answer)
<script>
<script>
document.write("There was an old woman ");
document.write("who lived in a shoe.<p />");
document.write("She had so many children, ");
document.write("she didn't know what to do.<p />");
document.write("But then they grew up ");
document.write("and she had no-one to handle.<p />");
document.write("So the old woman moved out ...<p />");
document.write("... and into a sandal!");
</script>
| <script language="JavaScript"> var x = 2; // x = 7; alert(x); </script> | The number displayed is 
 |  | 
 In Britain, we generally measure people's weight in stone and pounds (weight, not money), where 1 stone is equal to 14 pounds. Furthermore, 1 pound is equal to 0.454 kilogrammes (0.454 kg), so a weight in pounds can be converted into kilogrammes by multiplying it by 0.454.
In Britain, we generally measure people's weight in stone and pounds (weight, not money), where 1 stone is equal to 14 pounds. Furthermore, 1 pound is equal to 0.454 kilogrammes (0.454 kg), so a weight in pounds can be converted into kilogrammes by multiplying it by 0.454.
 (No, not that sort of pounds! Pounds weight!)
 (No, not that sort of pounds! Pounds weight!)
Write a program that uses prompt() twice, once to enter the weight in stone and then again to enter the remaining pounds (i.e. to enter a weight of 14 stone and 12 pounds, '14' would be entered the first time, and '3' the second time), and then displays the weight in kilogrammes.
I am grossly overweight, and as part of a strict diet I weigh myself once a week. I have two weighing scales - one weighs in stone and pounds and the other in kilogrammes. Unfortunately, I don't know which of the two is more accurate, and I have no way of calibrating them, so I weigh myself on each and then take an average of the two weights. Write a version of your previous program that allows me to enter both weights and then returns the average weight in kilogrammes.